Multiple choice

Sunita got married 8 years ago. Today her age is 9/7 times of her age at the time of her marriage. At present her daughter's age is one sixth of her age. What was her daughter's age 3 years ago?

  1. 2

  2. 6

  3. 3

  4. 4
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Sunita's age at the time of her marriage be x, making her present age x + 8. Since her present age is also 9/7 of her marriage age, we solve x + 8 = 9x/7 to find x = 28, meaning her present age is 36. Her daughter's present age is one-sixth of 36, which is 6, so three years ago the daughter was 3 years old.

AI explanation

Let Sunita's age at the time of her marriage be x years, which means her present age is x + 8. According to the problem, x + 8 = 9x divided by 7. Solving this gives 7x + 56 = 9x, so x = 28, making her present age 36 years. Her daughter's present age is one sixth of 36, which is 6 years, so 3 years ago her daughter was 3 years old.

Keep practicing — related questions