Multiple choice

The present ages of three friends are in the ratio of 4 : 7 : 9. Five years ago, the sum of their ages was 65. Find their present ages.

  1. 16 years, 28 years, 36 years

  2. 16 years, 28 years, 32 years

  3. 12 years, 14 years, 20 years

  4. 12 years, 30 years, 40 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let ages be 4x, 7x, 9x. Five years ago: (4x-5) + (7x-5) + (9x-5) = 65. 20x - 15 = 65. 20x = 80. x = 4. Ages: 16, 28, 36.

AI explanation

Let the present ages be 4x, 7x and 9x years. Five years ago, their ages would have been (4x - 5), (7x - 5) and (9x - 5), giving the sum 20x - 15. Equating this to 65 yields 20x = 80, so x = 4. The present ages are 16 years, 28 years and 36 years.

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