In the year 2002, the population of a town increased by 𝑝% with respect to its population in 2001, but due to the breakout of a communicable disease, the population of the town dropped by (𝑝 + 5)% in the year 2003 with respect to its population in 2002. If the total population of the town dropped by 8% in 2003 with respect to that in 2001 and, after it revived from the communicable disease, its population increased by 25% in 2004 with respect to that in 2003, then by what percent did the population of the town change in 2004 with respect to that in 2002?

Let the initial population in 2001 be 100, making the 2003 population 92 after the 8% drop. The population in 2004 increases by 25%, making it 92 multiplied by 1.25, which equals 115. To find the 2002 population, use the equation 115 equals the 2002 population multiplied by 1 minus the quantity p plus 5 divided by 100, which yields a 2002 population of 115. Therefore, the population in 2004 is exactly the same as the population in 2002, resulting in a 0% change.

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