Multiple choice

At the school cafeteria, there are 30 tables and each table can seat either 2 or 4 students. If there are a total of 80 students in one of the lunch sections, how many tables must seat exactly 4 students in this lunch section?

  1. 9

  2. 10

  3. 11

  4. 12
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B Correct answer
Explanation

Let x be the number of 4-student tables, y be the number of 2-student tables. x + y = 30. 4x + 2y = 80. From first, y = 30 - x. Substitute: 4x + 2(30 - x) = 80. 4x + 60 - 2x = 80. 2x = 20. x = 10.

AI explanation

Assume the number of 2-seater tables is x and the number of 4-seater tables is y. We are given that the total number of tables is 30, so x plus y equals 30, and the total seating capacity is 80, so 2x plus 4y equals 80. By multiplying the first equation by 2, we get 2x plus 2y equals 60; subtracting this from the second equation leaves 2y equals 20. Solving for y gives the result 10, meaning 10 tables must seat exactly 4 students.

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