What is the mean deviation of first 10 even natural numbers?
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5
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5.5
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10
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10.5
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NA
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A
Correct answer
Explanation
First 10 even numbers: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20. Mean = 11. Mean deviation = (1/10) * sum(|x_i - 11|). Sum = 9+7+5+3+1+1+3+5+7+9 = 50. Mean deviation = 50/10 = 5.
AI explanation
The first 10 even natural numbers are 2, 4, 6, up to 20, and their mean is calculated as 110 divided by 10, which is 11. The mean deviation is the sum of the absolute differences between each number and the mean, divided by the total number of observations. The absolute deviations are 9, 7, 5, 3, 1, 1, 3, 5, 7, and 9, which sum to 50; dividing this sum by 10 gives a mean deviation of 5.