Multiple choice

In 2006, the population of a city was 1,20,000. If net rate of increase in population is 1.5% per year, what will be the population in 2009?

  1. 1,24,092

  2. 1,25,481

  3. 1,26,781

  4. 1,28,964
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Population = 120000 * (1 + 0.015)^3 = 120000 * 1.045678375 = 125481.405. Rounded to the nearest whole number, it is 125481.

AI explanation

Use the compound growth formula for population: Final Population = Initial Population * (1 + Rate/100)^n. The time period from 2006 to 2009 is 3 years, so the calculation is 120000 * (1 + 0.015)^3. Evaluating this gives 120000 * 1.045678375, which equals 125481.

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