Multiple choice

Find the smallest number that, when divided by 12, 15, and 20, leaves a constant remainder of 4 in each case.

  1. 64

  2. 124

  3. 60

  4. 56

  5. 44
Reveal answer Fill a bubble to check yourself
A Correct answer
AI explanation

First, calculate the least common multiple of 12, 15, and 20, which is 60. Because the required number leaves a constant remainder of 4 when divided by these numbers, it must take the form of the LCM plus the remainder. Therefore, adding 4 to 60 yields the smallest such number, which is 64.

Keep practicing — related questions