Ten pipes of the same type can fill up a tank in $16$ minutes. If two pipes go out of order, how long will the remaining pipes take to fill the tank ?

Using the total work method, the total work required to fill the tank is ten pipes multiplied by sixteen minutes, giving one hundred sixty pipe-minutes. If two pipes go out of order, eight pipes remain available to do the work. Dividing the total work of one hundred sixty pipe-minutes by the eight remaining pipes results in a time of twenty minutes.

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