Multiple choice

Fifty seeds were selected at random from each of $5$ bags $A, B, C, D, E$ of seeds, and were kept under standardised conditions equally favourable to germination. After $20$ days, the number of seeds which had germinated in each collection were counted and recorded as follow : Bag $A$ $B$ $C$ $D$ $E$ Number of seeds germinated $40$ $48$ $42$ $39$ $41$ What is the probability of germination of $(i)$ more than $40$ seeds in a bag? $(ii)$ $49$ seeds in a bag? $(iii)$ more than $35$ seeds in a bag?

  1. $(i)\, 0.690$
    $(ii)\, 0.09$
    $(iii)\, 1$
  2. $(i)\, 0.80$
    $(ii)\, 0.006$
    $(iii)\, 1$
  3. $(i)\, 0.70$
    $(ii)\, 0.001$
    $(iii)\, 1$
  4. $(i)\, 0.60$
    $(ii)\, 0$
    $(iii)\, 1$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total bags = 5. (i) Bags with > 40 seeds are B(48), C(42), E(41), so 3/5 = 0.6. (ii) No bag has 49 seeds, so 0/5 = 0. (iii) All 5 bags have > 35 seeds, so 5/5 = 1.

AI explanation

Out of the 5 bags, 3 bags (B, C, and E) have more than 40 seeds germinating, making the first probability 3 divided by 5, which is 0.60. None of the bags contain exactly 49 germinated seeds, making the second probability 0 divided by 5, or 0. All 5 bags have more than 35 seeds germinating, making the third probability 5 divided by 5, which is 1. Therefore, the probability of germination of more than 40 seeds is 0.60, the probability of 49 seeds is 0, and the probability of more than 35 seeds is 1.