Multiple choice

Match the columns. Column-I Column-II (i) When an odd Integer 'a' is divided by $2$, then remainder r can be (p) $5$ (ii) When an integer 'a' whose unit digit is $4$ is divided by $5$, then remainder r can be (q) $1$ (iii) A whole number lying between $\sqrt{2}$ and $2\sqrt{2}$ is (r) $2$ (iv) If the digit at the units place of a number is $5$, then it is surely divisible by (s) $4$

  1. (i) $\rightarrow$ (p), (ii) $\rightarrow$ (r), (iii) $\rightarrow$ (s), (iv) $\rightarrow$ (q)
  2. (i) $\rightarrow$ (q), (ii) $\rightarrow$ (s), (iii) $\rightarrow$ (p), (iv) $\rightarrow$ (r)
  3. (i) $\rightarrow$ (p), (ii) $\rightarrow$ (r), (iii) $\rightarrow$ (q), (iv) $\rightarrow$ (s)
  4. (i) $\rightarrow$ (q), (ii) $\rightarrow$ (s), (iii) $\rightarrow$ (r), (iv) $\rightarrow$ (p)
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D Correct answer
Explanation

(i) Odd integer divided by 2 leaves remainder 1. (ii) Unit digit 4 divided by 5 leaves remainder 4. (iii) Whole number between sqrt(2) (1.414) and 2*sqrt(2) (2.828) is 2. (iv) Unit digit 5 is divisible by 5.

AI explanation

When an odd integer is divided by 2, the remainder is always 1, so (i) matches (q). An integer ending in 4 leaves a remainder of 4 when divided by 5, so (ii) matches (s). The value of the square root of 2 is about 1.414 and twice the square root of 2 is about 2.828, making 2 the only whole number between them, so (iii) matches (r). A number ending in 5 is surely divisible by 5, so (iv) matches (p). This gives the matching sequence as (i) -> (q), (ii) -> (s), (iii) -> (r), (iv) -> (p).

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