Solve the following equation: $\sqrt {2x - 3} = \sqrt {7 - 3x} $
Reveal answer
Fill a bubble to check yourself
Solve the following equation: $\sqrt {2x - 3} = \sqrt {7 - 3x} $
Square both sides: 2x - 3 = 7 - 3x. 5x = 10. x = 2. Check: sqrt(2*2 - 3) = sqrt(1) = 1. sqrt(7 - 3*2) = sqrt(1) = 1. Both sides match.
To solve the equation sqrt(2x - 3) = sqrt(7 - 3x), we square both sides to eliminate the square roots, yielding 2x - 3 = 7 - 3x. Grouping the variable terms on one side gives 5x = 10. Dividing by 5 results in x = 2, which also keeps the expressions under both radicals positive.