Solve the following equation: $x^2-3x=10$
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Solve the following equation: $x^2-3x=10$
5, -2
4, 2
3, 6
None
Rearrange the equation to x^2 - 3x - 10 = 0. Factor the quadratic: (x - 5)(x + 2) = 0. The solutions are x = 5 and x = -2.
To find the roots of the quadratic equation, first move 10 to the left side to get x squared minus 3x minus 10 equals 0. Factoring this expression gives (x minus 5) times (x plus 2) equals 0. Setting each factor to zero yields the roots 5 and negative 2.