Using the given equation alpha/beta + beta/alpha = 5/2, we combine the fractions to get (alpha^2 + beta^2)/(alpha*beta) = 5/2. Applying the algebraic identity alpha^2 + beta^2 = (alpha - beta)^2 + 2*alpha*beta, we substitute the absolute difference alpha - beta = 1 to find the numerator becomes 1 + 2*alpha*beta. This gives the proportion (1 + 2*alpha*beta)/(alpha*beta) = 5/2, which simplifies to 2 + 4*alpha*beta = 5*alpha*beta, meaning the product of the roots is alpha*beta = 2. Using the sum of roots formula, (alpha - beta)^2 = (alpha + beta)^2 - 4*alpha*beta, so 1 = (alpha + beta)^2 - 8, which means (alpha + beta)^2 = 9 and the sum is 3. Forming the quadratic equation x^2 - (sum)x + (product) = 0, we get x^2 - 3x + 2 = 0. The result is x^2 - 3x + 2 = 0.