Multiple choice

The sum of the root of the equation $mx^{2}-(m+n)x+1=0$ is

  1. $\dfrac{m+n}{m}$
  2. $\dfrac{-(m+n)}{m}$
  3. $\dfrac{1}{m+n}$
  4. $\dfrac{1}{m}$
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A Correct answer
Explanation

For a quadratic equation ax^2 + bx + c = 0, the sum of the roots is -b/a. Here, a=m, b=-(m+n), c=1. Sum = -(-(m+n))/m = (m+n)/m.

AI explanation

Using the sum of roots formula for a quadratic equation, we calculate -coefficient of x divided by coefficient of x^2. For the equation mx^2 - (m+n)x + 1 = 0, the sum is -[-(m+n)] divided by m. This simplifies to (m+n) divided by m.

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