The roots of the equation $x^4-1=0$, are?
- $1, 1, i, -i$
- $1, -1, i, -i$
- $1, -1, \omega, \omega^2$
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None of these
Reveal answer
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B
Correct answer
Explanation
x^4 - 1 = 0 => (x^2 - 1)(x^2 + 1) = 0. (x-1)(x+1)(x-i)(x+i) = 0. Roots are 1, -1, i, -i.
AI explanation
To find the roots of the equation, we set the polynomial to zero by writing x^4 - 1 = 0. Using the algebraic identity for the difference of squares, we factor it as (x^2 - 1)(x^2 + 1) = 0. This gives x^2 = 1, which yields 1 and -1, and x^2 = -1, which yields i and -i. The roots are 1, -1, i, and -i.