If $\alpha$ and $\beta$ are the roots of equation $x^{2}-ax(x+1)-b=0$ where $a,\ b\ \epsilon \ R-{(0)}$ and $a+b\neq =0$ then the value of $\dfrac{1}{\alpha ^{2}-a\alpha}+\dfrac{1}{\beta ^{2}-a\beta}-\dfrac{2}{a+b}$ is equal to

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