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Multiple choice

If $\alpha$, $\beta$ and $\gamma$ are the roots of the equation ${ x }^{ 3 }-x-1=0$, then $\dfrac { 1+\alpha }{ 1-\alpha } +\dfrac { 1+\beta }{ 1-\beta } +\dfrac { 1+\gamma }{ 1-\gamma }$ has the value

  1. $-5$
  2. $-1$
  3. $-7$
  4. $1$
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