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Multiple choice

If roots $\alpha$ and $\beta$ of the equation ${x}^{2}+px+q=0$ are such that $3\alpha+4\beta=7$ and $5\alpha-\beta=4$, then $(p,q)$ is equal to

  1. $(1,1)$
  2. $(-1,1)$
  3. $(-2,1)$
  4. $(2,1)$
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