If $x=1$ is common root of equations $ax^{2} +ax+3=0$ and $x^{2}+x+b=0$, then value of $ab$ will be:

Since x = 1 is a root of ax^2 + ax + 3 = 0, substitute x = 1 to get a(1)^2 + a(1) + 3 = 0, which simplifies to 2a + 3 = 0 and yields a = -3/2. Since x = 1 is also a root of x^2 + x + b = 0, substitute x = 1 to get 1^2 + 1 + b = 0, which simplifies to 2 + b = 0 and yields b = -2. The product ab is then (-3/2) * (-2) = 3.

• Thanks
• Wrong explanation