Multiple choice

The equation whose roots are $n ^ { th }$ power of the roots of the equation, $x ^ { 2 } - 2 x \cos \theta + 1 = 0$ is given by

$( x + \cos n \theta ) ^ { 2 } + \sin ^ { 2 } n \theta = 0$
$( x - \cos n \theta ) ^ { 2 } + \sin ^ { 2 } n \theta = 0$
$x ^ { 2 } + 2 x \cos n \theta + 1 = 0$
$x ^ { 2 } - 2 x \cos n \theta + 1 = 0$

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