Solve the given equation by the method of Completion of Squares: ${x}^{2}+4x+4=0$?
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Solve the given equation by the method of Completion of Squares: ${x}^{2}+4x+4=0$?
x^2 + 4x + 4 = 0 is (x+2)^2 = 0. Thus, x = -2.
Using the method of completing the squares, the given equation x squared plus 4x plus 4 equals 0 can be written as x squared plus 2 times x times 2 plus 2 squared equals 0. Applying the algebraic identity a squared plus 2ab plus b squared equals (a plus b) squared, the equation becomes (x plus 2) squared equals 0. Taking the square root of both sides gives x plus 2 equals 0, which means x equals negative 2.