Multiple choice

What is the reciprocal product of the roots for the equation $48x^{2}-6x + 36$?

  1. $\dfrac{4}{3}$
  2. $\dfrac{3}{4}$
  3. $\dfrac{1}{3}$
  4. $\dfrac{4}{-3}$
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A Correct answer
Explanation

For ax^2 + bx + c = 0, the roots are r1, r2. The reciprocal product is (1/r1) * (1/r2) = 1/(r1*r2) = 1/(c/a) = a/c. Here a=48, c=36. So 48/36 = 4/3.

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