Multiple choice

Which of the following option is the standard form of the mentioned quadratic equation? $\displaystyle\frac{m^{2}\, +\, 5}{m^{2}}\, =\, -3$

  1. $-2m^{2}\, -\, 0m\, +\, 5\, =\,0$
  2. $4m^{2}\, +\, 0m\, +\, 5\, =\,0$
  3. $4m^{2}\, +\, 0m\, -\, 5\, =\,0$
  4. $-2m^{2}\, -\, 0m\, -\, 5\, =\,0$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Starting with (m^2 + 5) / m^2 = -3, multiply both sides by m^2 to get m^2 + 5 = -3m^2. Adding 3m^2 to both sides results in 4m^2 + 5 = 0, which is 4m^2 + 0m + 5 = 0.

AI explanation

Multiply the entire equation by m^2 to clear the denominator, yielding m^2 + 5 = -3m^2. Add 3m^2 to both sides to set the equation to zero, resulting in 4m^2 + 5 = 0. Written in the standard form ax^2 + bx + c = 0, this becomes 4m^2 + 0m + 5 = 0.

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