Multiple choice

Find the volume strength of $H_2O_2$ solution prepared by mixing of $250$ mL of $3N \,H_2O_2$ & 750 mL of 1N $H_2O_2$ solution.

  1. $1.5$ V
  2. $8.4$ V
  3. $5.6$ V
  4. $11.2$ V
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B Correct answer
Explanation

Normality of mixture = (N1V1 + N2V2) / (V1 + V2) = (3*250 + 1*750) / 1000 = 1500 / 1000 = 1.5 N. Volume strength = Normality * 5.6 = 1.5 * 5.6 = 8.4 V.

AI explanation

Using the dilution formula N1V1 plus N2V2 equals N3V3, we calculate the final normality as (3 multiplied by 250) plus (1 multiplied by 750) divided by 1000. This gives a final normality of 1.5 N for the mixture. Since volume strength equals normality multiplied by 5.6, we multiply 1.5 by 5.6 to get the result. The volume strength of the resulting solution is 8.4 V.

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