Multiple choice

A 700 g solid cube having an edge of length 10 cm floats in water. What volume of the cube is outside water ?

  1. $300 cm^3$
  2. $600 cm^3$
  3. $150 cm^3$
  4. $450 cm^3$
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A Correct answer
Explanation

The cube floats, so the buoyant force equals the weight of the cube (700g). The volume of water displaced is 700 cm^3 (since density of water is 1g/cm^3). Total volume of the cube is 10*10*10 = 1000 cm^3. Volume outside water = Total volume - Displaced volume = 1000 - 700 = 300 cm^3.

AI explanation

Using Archimedes' principle, the mass of the cube equals the mass of the displaced water, so 700 g equals the volume submerged times the water density of 1 g/cm^3. The submerged volume of the cube is therefore 700 cm^3. The total volume of the cube is 10 cm * 10 cm * 10 cm, which equals 1000 cm^3. Subtracting the submerged volume from the total volume gives the volume outside the water as 1000 cm^3 minus 700 cm^3, resulting in 300 cm^3.

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