Multiple choice

A mixture of $Nal$ and $Nacl$ on reaction with ${H_2}S{O_4}$ gave $N{a_2}S{O_4}$ equal to weight of original mixture taken. The percentage of $Nal$ in the mixture is

  1. $82.38$
  2. $26.38$
  3. $62.38$
  4. $28.38$
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B Correct answer
AI explanation

Let the mass of sodium iodide be x grams and the mass of sodium chloride be y grams. We convert both salts to sodium sulfate, using the mass ratios of 142 divided by 150 for the iodide and 142 divided by 117 for the chloride. The equation is 142 divided by 150 multiplied by x plus 142 divided by 117 multiplied by y equals the original total mass of x plus y. Solving this equation gives x equal to 0.2638 multiplied by the total mass. The percentage of sodium iodide is 26.38.

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