If the equation $\dfrac{a}{x-a}+\dfrac{b}{x-b}=1$ has roots equal in magnitude but opposite in sign, then the value of $a+b$ is-
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If the equation $\dfrac{a}{x-a}+\dfrac{b}{x-b}=1$ has roots equal in magnitude but opposite in sign, then the value of $a+b$ is-