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Multiple choice

Consider the equation $|x^{2}-4|x|+3|=p$

  1. For $p=2$ the equation has four solutions
  2. For $p=2$ the equation has eight solutions
  3. There exists only one real value of $p$ for which the equation has odd number of solutions
  4. Sum of roots of the equation is zero irrespective of value of $p$
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