V, Litre of solution A (Resistance = 50ohm) is mixed with $V_2$ Litre of solution B (Resistance = 100) Resistance of final solution is 80 ohm then $\frac { V_2 }{ V_1 } $ will be: (using same cell)

Since conductance is the reciprocal of resistance and the volumes are additive, the total conductance is the weighted average of the individual conductances by volume. Setting up the equation based on conductances gives V1 multiplied by (1 divided by 50) plus V2 multiplied by (1 divided by 100) equals (V1 plus V2) multiplied by (1 divided by 80). Solving this linear equation results in the ratio of V2 to V1 being 3.

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