Multiple choice

Ravi borrowed Rs45000 from Sahil A part of the sum is borrowed at 10% pa under simple interest for 4 years and the remaining part at 11% pa under simple interest for $\displaystyle 4\frac{1}{2}$ years If the total interest earned by Sahil is Rs 19900 then find the sum borrowed at each rate

  1. 10000, 35000

  2. 25000, 20000

  3. 15000, 30000

  4. 5000, 40000
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let x be the sum at 10% for 4 years, and (45000-x) at 11% for 4.5 years. Interest = (x * 0.1 * 4) + ((45000-x) * 0.11 * 4.5) = 19900. Solving gives x = 25000.

AI explanation

Let the first part be Rs. x, making the second part Rs. (45000 - x). Using the simple interest formula, the total interest is (x * 10 * 4) / 100 + ((45000 - x) * 11 * 4.5) / 100 = 19900. This simplifies to 0.4x + 22275 - 0.495x = 19900. Solving for x gives 0.095x = 2375, so x = 25000. The two sums borrowed are Rs. 25000 and Rs. 20000.

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