Multiple choice

Let $\alpha(a)$ ans $\beta(a)$ be the roots of the equation $\left( \sqrt [ 3 ]{ 1+a } -1 \right) { x }^{ 2 }+\left( \sqrt { 1+a } -1 \right) x+\left( \sqrt [ 6 ]{ 1+a } -1 \right) =0$ Where $a>-1$. Then $\displaystyle \lim _{ { a\rightarrow 0 }^{ + } }{ \alpha \left( a \right) } =l$ and $\displaystyle \lim _{ { a\rightarrow 0 }^{ + } }{ \beta \left( a \right) } =m$ where $l

  1. $3/2$
  2. $-3/2$
  3. $1/2$
  4. $-1/2$
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A Correct answer