Multiple choice

If $16{X}^{2}-8X+1=0$, then the roots of the equations are_____.

  1. $(1/4,1/4)$
  2. $(1.3/-1)$
  3. $(2,3/2)$
  4. $(2/3.1)$
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A Correct answer
Explanation

16x^2 - 8x + 1 = 0 is (4x - 1)^2 = 0. The roots are 1/4 and 1/4.

AI explanation

We factor the quadratic equation 16 x squared minus 8x plus 1 equals 0 using the perfect square identity, giving (4x minus 1) squared equals 0. Setting the factor to zero, 4x minus 1 equals 0, yields x equals 1 divided by 4. Since the discriminant is zero, the roots are equal, resulting in the pair (1/4, 1/4).