Multiple choice

Mohan lent some amount of money at $9\%$ simple interest and an equal amount of money at $10\%$ simple interest each for $2$ years. If his total interest was Rs. $760$, what amount was lent in each case?

  1. Rs. $1700$
  2. Rs. $1800$
  3. Rs. $1900$
  4. Rs. $2000$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the amount be P. SI1 = (P * 9 * 2) / 100 = 0.18P. SI2 = (P * 10 * 2) / 100 = 0.20P. Total SI = 0.38P = 760. P = 760 / 0.38 = 2000.

AI explanation

Let the equal amount lent in each case be P. The total simple interest is the sum of the interests from both accounts, calculated as (P x 9 x 2) / 100 plus (P x 10 x 2) / 100. This simplifies to 18P/100 plus 20P/100, equaling 38P/100. Setting this equal to the total interest of Rs. 760 gives 38P/100 = 760, so P = 2000. The amount lent in each case was Rs. 2000.

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