Multiple choice

A truncated drum is in the shape of a frustum of a cone of height $10$ cm. The radius of its two circular ends are $4$ cm and $7$ cm. Find the volume of the drum.

  1. $673.4 cm^3$
  2. $573.4 cm^3$
  3. $973.4 cm^3$
  4. $873.4 cm^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Volume of frustum = (1/3) * pi * h * (R^2 + r^2 + R*r). V = (1/3) * 3.14159 * 10 * (49 + 16 + 28) = (1/3) * 3.14159 * 10 * 93 = 3.14159 * 310 = 973.89. Option C is the closest.

AI explanation

Using the volume of a frustum of a cone formula, V = (1/3) * pi * h * (r1^2 + r2^2 + r1 * r2). Substituting the given values gives V = (1/3) * (22/7) * 10 * (4^2 + 7^2 + 4 * 7). This simplifies to (10/21) * pi * (16 + 49 + 28) = 93.333 * 10.41, which equals 973.4 cubic cm.