Let $-\frac { \pi }{ 6 } <\theta <\frac { \pi }{ 12 } .$ Suppose $ { \alpha }{ 1 } $ and $ { \beta }{ 1 } $ are the roots of the equation $ { x }^{ 2 }-2xsec\theta +1=0 $ and $ { \alpha }{ 2 }$ and $ { \beta }{ 2 } $ are the roots of the equation $ { x }^{ 2 }+2xtan\theta -1=0. $ If $ { \alpha }{ 1 }>\beta _{ 1 } $ and $ { \alpha }{ 2 }>{ \beta }{ 2 }, $ Then $ { \alpha }{ 1 }+{ \beta }_{ 2 } $ equals