Find the volume of the frustum cone whose base and top radius is $0.1 cm$ and $0.01 cm$ respectively. The height of the cone is $3cm$. (Use $\pi$ = 3).

The volume of a frustum of a cone is calculated as V = 1/3 * pi * h * (R^2 + r^2 + R*r). Plugging in the given values results in V = 1/3 * 3 * 3 * (0.1^2 + 0.01^2 + 0.1*0.01). The sum of the radii terms is 0.0111, making the total volume 0.0333 cm^3.

• Thanks
• Wrong explanation