Multiple choice

A mixture contains $N_2O_4$ and $NO_2$ in the ratio $2:1$ by volume. The vapour denstiy of the mixture is

  1. 45.4

  2. 49.8

  3. 32.6

  4. 38.3
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The average molar mass by volume is (2 × 92 + 1 × 46)/3 = 76.67. Vapour density is half the molar mass, so it is approximately 38.3. Therefore, option D is correct.

AI explanation

Assuming a total volume of 3 units for the mixture, you have 2 moles of N2O4 and 1 mole of NO2. The molecular weights are 92 for N2O4 and 46 for NO2. The average molecular weight of the mixture is ((2 * 92) + (1 * 46)) / 3, which equals 230 / 3 = 76.67. The vapour density is half of the molecular weight, so the vapour density of the mixture is 76.67 / 2, which is 38.3.

Keep practicing — related questions