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Multiple choice

If $\alpha ,\beta $ be the root of $x^{2}-3x+4=0$, then the equation whose roots are $\alpha ^{3}-4\alpha ^{2}+7\alpha -3$ and $ \beta ^{3}-2\beta ^{2}+\beta +6$ is

  1. $x^{2}-3x+2=0$
  2. $x^{2}-2x+2=0$
  3. $x^{2}-x+1=0$
  4. $x^{2}-2x+1=0$
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