If $\alpha,\beta,\gamma$ are the roots of the equation $\mathrm{x}^{3}+4\mathrm{x}+1=0$, then $(\alpha+\beta)^{-1}+(\beta+\gamma)^{-1}+(\gamma+\alpha)^{-1}=$
Reveal answer
Fill a bubble to check yourself
If $\alpha,\beta,\gamma$ are the roots of the equation $\mathrm{x}^{3}+4\mathrm{x}+1=0$, then $(\alpha+\beta)^{-1}+(\beta+\gamma)^{-1}+(\gamma+\alpha)^{-1}=$