Multiple choice

Choose the most appropriate option. $60$kg of an alloy X is mixed with $100$ kg of an alloy Y. If alloy X has lead and tin in the ratio of $3:2$ and alloy Y has tin and copper in the ratio of $1:4$, then the amount of tin in the new alloy is?

  1. $53$ kgs
  2. $80$ kgs
  3. $36$ kgs
  4. $44$ kgs
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Alloy X (60 kg) has lead and tin in ratio 3:2, so tin = (2/5)*60 = 24 kg. Alloy Y (100 kg) has tin and copper in ratio 1:4, so tin = (1/5)*100 = 20 kg. Total tin = 24 + 20 = 44 kg.

AI explanation

In alloy X, the amount of tin is 2/5 of the total weight, so multiplying this fraction by 60 kg gives 24 kg of tin. In alloy Y, the amount of tin is 1/5 of the total weight, so multiplying this fraction by 100 kg gives 20 kg of tin. Adding these two amounts together results in 24 kg plus 20 kg, yielding 44 kg of tin in the new alloy.

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