The roots of the equation $(x-3)^2=3$ are
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The roots of the equation $(x-3)^2=3$ are
(x-3)^2 = 3 => x-3 = +/- sqrt(3) => x = 3 +/- sqrt(3).
To solve (x - 3)^2 = 3, take the square root of both sides, introducing both positive and negative roots. This gives x - 3 = sqrt(3) or x - 3 = -sqrt(3). Adding 3 to both sides results in x = 3 + sqrt(3) and x = 3 - sqrt(3).