Multiple choice

A bucket is in the shape of the frustum with the top and bottom circle area is $250$ and $150$ $m^2$. The height of the bucket is $27$ m. Find the volume.

  1. $2,121.60$ $m^3$
  2. $3,410.15$ $m^3$
  3. $5,342.76$ $m^3$
  4. $4,320.15$ $m^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The volume of a frustum is (h/3) * (A1 + A2 + sqrt(A1 * A2)). Here, h=27, A1=250, A2=150. Volume = (27/3) * (250 + 150 + sqrt(250 * 150)) = 9 * (400 + sqrt(37500)) = 9 * (400 + 193.647) = 9 * 593.647 = 5342.82. Option C is the closest.

AI explanation

Using the volume of a frustum formula, V = (h/3) * (A1 + A2 + sqrt(A1 * A2)). Substituting the given values gives V = (27/3) * (250 + 150 + sqrt(250 * 150)). This calculates to 9 * (400 + sqrt(37500)), which is 9 * (400 + 193.64) for a total volume of 5342.76 m^3.

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