The sum of real roots of the equation $\displaystyle x^{2}+|x|-6=0$ is
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The sum of real roots of the equation $\displaystyle x^{2}+|x|-6=0$ is
none of these
The equation is x^2 + |x| - 6 = 0. If x >= 0, x^2 + x - 6 = 0 -> (x+3)(x-2) = 0, so x = 2. If x < 0, x^2 - x - 6 = 0 -> (x-3)(x+2) = 0, so x = -2. The sum of roots 2 + (-2) = 0.
For x greater than or equal to 0, the equation becomes x squared plus x minus 6 equals 0. Factoring gives (x plus 3)(x minus 2) equals 0, and the only non-negative root is 2. For x less than 0, the equation becomes x squared minus x minus 6 equals 0. Factoring gives (x minus 3)(x plus 2) equals 0, and the only negative root is negative 2. The sum of the real roots 2 and negative 2 is 0.