$60$ % of $H_{2}$ and $40$% of $O_{2}$ by volume are present in a mixture at a pressure of $100$ $mm$. Pressure exerted by $H_{2}$ is:

The pressure exerted by a gas in a mixture is its partial pressure, calculated by multiplying the total pressure by the gas's volume fraction. For hydrogen, this gives 100 mm multiplied by 0.60, which equals 60 mm. The pressure exerted by hydrogen is 60 mm.

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