The product of the roots of the equation $(x - 2)^2 - 3(x - 2) + 2 = 0$ is
Reveal answer
Fill a bubble to check yourself
The product of the roots of the equation $(x - 2)^2 - 3(x - 2) + 2 = 0$ is
Let y = x - 2. The equation becomes y^2 - 3y + 2 = 0. Factoring gives (y - 1)(y - 2) = 0, so y = 1 or y = 2. Substituting back, x - 2 = 1 (x = 3) or x - 2 = 2 (x = 4). The product of roots 3 * 4 is 12.
Treating the given expression as a quadratic in terms of (x minus 2), we factor it to get ((x minus 2) minus 1)((x minus 2) minus 2) equals 0. This simplifies to (x minus 3)(x minus 4) equals 0, yielding roots of 3 and 4. The product of these roots is 3 times 4, which equals 12.