Multiple choice If one root of the equation $ ax^{2}+bx+c=0 $ is $3-4i$, then $a+b+c$ is equal to $40$ $36$ $-20$ $20$ Reveal answer Fill a bubble to check yourself D Correct answer Explanation Since coefficients are real, if 3-4i is a root, then 3+4i is also a root. Sum of roots = 6 = -b/a. Product of roots = 3^2 + 4^2 = 25 = c/a. Equation is x^2 - 6x + 25 = 0. a=1, b=-6, c=25. a+b+c = 1 - 6 + 25 = 20.