Solve the following equation for $x:125={5}^{2x-1}$.
Reveal answer
Fill a bubble to check yourself
Solve the following equation for $x:125={5}^{2x-1}$.
125 = 5^3. So 5^3 = 5^(2x-1). Equating exponents: 3 = 2x - 1, 4 = 2x, x = 2.
Express both sides of the equation with the same base to write 125 as 5^3, giving 5^3 = 5^(2x - 1). Since the bases are the same, set the exponents equal to each other: 3 = 2x - 1. Add 1 to both sides to get 4 = 2x, so x = 2.