Solve the following equation for $x$. $\cfrac { 2x+3 }{ 5 } -10=\cfrac { 4-3x }{ 2 } $
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Solve the following equation for $x$. $\cfrac { 2x+3 }{ 5 } -10=\cfrac { 4-3x }{ 2 } $
(2x+3)/5 - 10 = (4-3x)/2. Multiply by 10: 2(2x+3) - 100 = 5(4-3x) => 4x + 6 - 100 = 20 - 15x => 19x = 114 => x = 6.
To solve the equation (2x + 3)/5 - 10 = (4 - 3x)/2, we first multiply the entire equation by the least common multiple of 10 to clear the fractions. This gives 2(2x + 3) - 100 = 5(4 - 3x), which expands to 4x + 6 - 100 = 20 - 15x. Combining the terms yields 4x - 94 = 20 - 15x. Adding 15x to both sides and adding 94 to both sides results in 19x = 114. Dividing by 19 gives x = 6.