Solve the following equation for $x$. $3(2x+5)=10x+7+2(x-8)$
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Solve the following equation for $x$. $3(2x+5)=10x+7+2(x-8)$
3(2x+5) = 6x + 15. 10x + 7 + 2(x-8) = 10x + 7 + 2x - 16 = 12x - 9. Set 6x + 15 = 12x - 9. 24 = 6x, so x = 4.
First, distribute the values into the parentheses to expand the equation to 6x + 15 = 10x + 7 + 2x - 16. Combining the like terms on the right side gives 6x + 15 = 12x - 9. Solving for x, we subtract 6x from both sides and add 9 to both sides to get 24 = 6x. Dividing by 6 yields x = 4.