The ratio of ink and water in $66$ litres of adulterated ink is $5 : 1$. The quantity of water to be added in the mixture to make the ratio of ink and water $5 : 3$ is

In the original 66 litre mixture, the quantity of water is 1/6 of 66, which is 11 litres, while the ink is 55 litres. Let x litres of water be added to achieve a 5:3 ratio, making the equation 55 / (11 + x) = 5/3. Solving this gives 165 = 55 + 5x, so 5x = 110 and x = 22. The required amount of water to add is 22 litres.

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